Build A List Of Files In A Directory

Submitted by Nathan Clouse on 12/06/11.

Last modified: 

02/15/17

Tags: 

You can use the following function to build a list of files for a given directory:

static List buildFilesList(FilePath _path, FileName _searchPattern = '')
{
    int i, length;
    List ret = new List(Types::String);
    System.Array files;
    System.Exception e;
    str f;
    new InteropPermission(InteropKind::ClrInterop).assert();

    try
    {
        if(_searchPattern != '') files = System.IO.Directory::GetFiles(_path, _searchPattern);
        else files = System.IO.Directory::GetFiles(_path);

        if(files)
        {
            length = files.get_Length();

            for(i = 0; i < length; i++)
            {
                f = files.GetValue(i);
                ret.addEnd(f);
            }
        }
    }
    catch(Exception::CLRError)
    {
        throw error(AifUtil::getClrErrorMessage());
    }

    CodeAccessPermission::revertAssert();

    return ret;
}